Instant Apps Camera Intent

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I developed and Instant App which one I would like to take a picture with the camera. Everything work if I launch the Installed App. But with Instant App, I get the following error :

java.lang.SecurityException: Not allowed to start activity Intent { act=android.media.action.IMAGE_CAPTURE launchParam=MultiScreenLaunchParams { mDisplayId=0 mFlags=0 }

Here my code :

AndroidManifest.xml

<uses-permission android:name="android.permission.CAMERA" />

Activity :

private static int CAMERA_REQUEST = 1234;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_goodbye);

findViewById(R.id.mainButton).setOnClickListener(new View.OnClickListener() {
      @Override
      public void onClick(View view) {
          startCamera();
      }
  });
}

private void startCamera() {
    if (ContextCompat.checkSelfPermission(this, Manifest.permission.CAMERA) != PackageManager.PERMISSION_GRANTED) {
        if (ActivityCompat.shouldShowRequestPermissionRationale(this, Manifest.permission.CAMERA)) {
        } else {
            ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.CAMERA}, CAMERA_REQUEST);
        }
    } else {
        Intent cameraIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
        startActivityForResult(cameraIntent, CAMERA_REQUEST);
    }
}

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    super.onRequestPermissionsResult(requestCode, permissions, grantResults);
    startCamera();
}


protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == CAMERA_REQUEST) {
        Bitmap bmp = (Bitmap)data.getExtras().get("data");
        ((ImageView)findViewById(R.id.mainImageView)).setImageBitmap(bmp);
    }
}

I develop on device (samsung) with Android 7.0. I checked available permission and Camera is that's why it's should work. (https://developer.android.com/topic/instant-apps/faqs.html#available-permissions) Thanks in advance.

3 Answers
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