Dispatching C++ generated files into srcs and hdrs

In the Bazel official documentation there is an example explaining how to create a Java library built from regular java files and files generated by a :gen_java_srcs rule. I rewrite this code here for ease of reading:

java_library(
    name = "mylib",
    srcs = glob(["*.java"]) + [":gen_java_srcs"],
    deps = "...",
)

genrule(
    name = "gen_java_srcs",
    outs = [
        "Foo.java",
        "Bar.java",
    ],
    ...
)

Now in a C++ perspective, I am in a scenario where the genrule generates two kind of files: .hpp and .cpp:

genrule(
    name = "gen_cpp_srcs",
    outs = [
        "myFile_1.hpp","myFile_2.hpp",...,"myFile_N.hpp",
        "myFile.cpp","myFile_2.cpp",...,"myFile_N.cpp",
    ],
    ...
)

where N is some tens.

My problem/question is: how to write the cc_library rule, with an automatic dispatching of the hpp and cpp files into hdrs and srcs field?

I want something like:

cc_library(
    name = "mylib",
    srcs = glob(["*.cpp"]) + (howto: .cpp files of [":gen_cpp_srcs"]),
    hdrs = glob(["*.hpp"]) + (howto: .hpp files of [":gen_cpp_srcs"]),
    ...
)

Some magic like:

output_filter(":gen_cpp_srcs","*.cpp")

would be perfect, but I do not know enough of Bazel to make it real.