I want to get a 2-D torch.Tensor with size [a,b] filled with values from a uniform distribution (in range [r1,r2]) in PyTorch.
I want to get a 2-D torch.Tensor with size [a,b] filled with values from a uniform distribution (in range [r1,r2]) in PyTorch.
Utilize the torch.distributions package to generate samples from different distributions.
For example to sample a 2d PyTorch tensor of size [a,b] from a uniform distribution of range(low, high) try the following sample code
import torch
a,b = 2,3 #dimension of the pytorch tensor to be generated
low,high = 0,1 #range of uniform distribution
x = torch.distributions.uniform.Uniform(low,high).sample([a,b])
To get a uniform random distribution, you can use
torch.distributions.uniform.Uniform()
example,
import torch
from torch.distributions import uniform
distribution = uniform.Uniform(torch.Tensor([0.0]),torch.Tensor([5.0]))
distribution.sample(torch.Size([2,3])
This will give the output, tensor of size [2, 3].
Please Can you try something like:
import torch as pt
pt.empty(2,3).uniform_(5,10).type(pt.FloatTensor)
This answer uses NumPy to first produce a random matrix and then converts the matrix to a PyTorch tensor. I find the NumPy API to be easier to understand.
import numpy as np
torch.from_numpy(np.random.uniform(low=r1, high=r2, size=(a, b)))
PyTorch has a number of distributions built in. You can build a tensor of the desired shape with elements drawn from a uniform distribution like so:
from torch.distributions.uniform import Uniform
shape = 3,4
r1, r2 = 0,1
x = Uniform(r1, r2).sample(shape)
See this for all distributions: https://pytorch.org/docs/stable/distributions.html#torch.distributions.uniform.Uniform
This is the way I found works:
# generating uniform variables
import numpy as np
num_samples = 3
Din = 1
lb, ub = -1, 1
xn = np.random.uniform(low=lb, high=ub, size=(num_samples,Din))
print(xn)
import torch
sampler = torch.distributions.Uniform(low=lb, high=ub)
r = sampler.sample((num_samples,Din))
print(r)
r2 = torch.torch.distributions.Uniform(low=lb, high=ub).sample((num_samples,Din))
print(r2)
# process input
f = nn.Sequential(OrderedDict([
('f1', nn.Linear(Din,Dout)),
('out', nn.SELU())
]))
Y = f(r2)
print(Y)
but I have to admit I don't know what the point of generating sampler is and why not just call it directly as I do in the one liner (last line of code).
Comments:
Reference:
Pytorch (now?) has a random integer function that allows:
torch.randint(low=r1, high=r2, size=(1,), **kwargs)
and returns uniformly sampled random integers of shape size in range [r1, r2).
https://pytorch.org/docs/stable/generated/torch.randint.html