Destructor call in a comma-separated expression

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consider the following example program:

#include <iostream>
using namespace std;
struct t
{
    ~t() {cout << "destroyed\n"; }
};
int main()
{
    cout << "test\n";
    t(), cout << "doing stuff\n";
    cout << "end\n";
}

The output I get with GCC 4.9.2 is:

test 
doing stuff 
destroyed 
end

cpp.sh link: http://cpp.sh/3cvm

However according to cppreference about the comma operator:

In a comma expression E1, E2, the expression E1 is evaluated, its result is discarded, and its side effects are completed before evaluation of the expression E2 begins

I'd expect ~t() to be called before cout << "doing stuff"

Is this a standard behavior? If so, where is it defined in the standard?

2 Answers
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