Is there a way to get the type name of a trait?

I'm trying to use std::intrinsics::type_name to get the type name of a trait but can't compile it:

#![feature(core_intrinsics)]

use std::intrinsics::type_name;

trait TestTrait: Sized {
    fn test(&self);
}

struct MyStruct {}

struct GetType {}

impl GetType {
    fn test_type<T: ?Sized>() {
        let test = unsafe { type_name::<T>() };
        println!("{:?}", test);
    }
}

fn main() {
    GetType::test_type::<i32>();
    GetType::test_type::<MyStruct>();
    GetType::test_type::<TestTrait>();
}

Here is the error I get from the compiler

error[E0038]: the trait `TestTrait` cannot be made into an object
  --> src/main.rs:23:30
   |
23 |         GetType::test_type::<TestTrait>();
   |                              ^^^^^^^^^ the trait `TestTrait` cannot be made into an object
   |
   = note: the trait cannot require that `Self : Sized`

Here is the output of that test when I comment the line GetType::test_type::<TestTrait>();

"i32"
"MyStruct"

Is there a way to solve this or to get the type name of a trait?

Working solution thanks to @evotopid

#![feature(core_intrinsics)]

use std::intrinsics::type_name;

trait TestTrait { // <--- remove `: Sized` constraint from here 
    fn test(&self);
}

struct MyStruct {}

struct GetType {}

impl GetType {
    fn test_type<T: ?Sized>() { // <--- trick is in that bound
        let test = unsafe { type_name::<T>() };
        println!("{:?}", test);
    }
}

fn main() {
    GetType::test_type::<i32>();
    GetType::test_type::<MyStruct>();
    GetType::test_type::<TestTrait>();
}

Leading to the following output

"i32"
"MyStruct"
"TestTrait"