Copy constructor of thrown object throws - why thrown object is still thrown?

Mind the following code:

struct exception_in_copy_constructor
{
    exception_in_copy_constructor() = default;
    ~exception_in_copy_constructor() = default;
    exception_in_copy_constructor(const exception_in_copy_constructor& other) 
    { 
        throw std::exception(":-(");
    }
};

Now, it is clear that when I throw this object, an std::exception will be thrown.

So lets look at the following code:

try
{    
    exception_in_copy_constructor ecc;
    throw ecc;
}
catch(exception_in_copy_constructor& ecc)
{
    printf("IN exception_in_copy_constructor&\r\n");
}
catch(std::exception& ex)
{
    printf("IN std::exception&\r\n");
}

I would expect the before ecc would be thrown, an std::exception will be thrown, and because of that, ecc will never be thrown. The code above confirmed that by printing "IN std::exception&"

BUT mind this code:

try
{    
    exception_in_copy_constructor ecc;
    throw ecc;
}
catch(exception_in_copy_constructor& ecc)
{
    printf("IN exception_in_copy_constructor&\r\n");
}

I would expect that nothing will get caught, but to my surprise, catch(exception_in_copy_constructor& ecc) caught the exception (?!?!)

Can anyone explain what is going on?

I am using VS2015

Thanks!

EDIT: Users wrote they cannot reproduce, so I am writing the whole code as it is on my computer. Also, I am using VS2015, debug, x64 (It also reproduce in release).

Here is the code:

int main()
{
    struct exception_in_copy_constructor
    {
        exception_in_copy_constructor() = default;
        ~exception_in_copy_constructor() = default;
        exception_in_copy_constructor(const exception_in_copy_constructor& other)
        {
            throw std::exception(":-(");
        }
    };

    try
    {
        exception_in_copy_constructor ecc;
        throw ecc;
    }
    catch(exception_in_copy_constructor&)
    {
        printf("We will never get here!\r\n");
    }

    return 0;
}