How to output every argument of a Bash function?

I want to output all arguments of a function one by one.
The function can receive many arguments, $# is the length of arguments.

showArg(){
    num=$#
    for order in `seq 1 ${num}`
    do
        echo $order
    done
}

To execute it.

showArg  x1 x2 x3 
1
2
3

How to fix the echo statement echo $order to get such the following output?

x1
x2
x3

I have tried echo $$order.

To call every argument with "$@" in for loop can list it, but it is not the way I expected.

showArg(){
    for var in "$@"
    do
        echo "$var"
    done
}