Overriding trait method with default parameter

Assume the following example - when executed returns - "fatherfather"

trait Action {
    def doSomething(s:String = "father") = s
}

class RevokeAction extends Action{
    override def doSomething(s:String) = {
        s + s
    }
}

object HelloWorld {
  def main(args: Array[String]): Unit = {
    val revokeAction = new RevokeAction()
    revokeAction.doSomething()
  }
}

Looking at what the compiler does - gives a better explanation of what is going on

package <empty> {
  abstract trait Action extends Object {
    def doSomething(s: String): String = s;
    <synthetic> def doSomething$default$1(): String = "father";
    def /*Action*/$init$(): Unit = {
      ()
    }
  };
  class RevokeAction extends Object with Action {
    <synthetic> def doSomething$default$1(): String = RevokeAction.super.doSomething$default$1();
    override def doSomething(s: String): String = s.+(s);
    def <init>(): RevokeAction = {
      RevokeAction.super.<init>();
      RevokeAction.super./*Action*/$init$();
      ()
    }
  };
  object HelloWorld extends Object {
    def main(args: Array[String]): Unit = {
      val revokeAction: RevokeAction = new RevokeAction();
      {
        revokeAction.doSomething(revokeAction.doSomething$default$1());
        ()
      }
    };
    def <init>(): HelloWorld.type = {
      HelloWorld.super.<init>();
      ()
    }
  }
}

Can please elaborate why this is the expected behavior?