Only show slot if it has content

user_2708607 0
Viewed 83306

Is there a way to only display a slot if it has any content?

For example, I'm building a simple Card.vue component, and I only want the footer displayed if the footer slot has content:

Template

<template>
    <div class="panel" :class="panelType">
        <div class="panel-heading">
            <h3 class="panel-title">
                <slot name="title">
                    Default Title
                </slot>
            </h3>
        </div>

        <div class="panel-body">
            <slot name="body"></slot>
            
            <p class="category">
                <slot name="category"></slot>
            </p>
        </div>

        <div class="panel-footer" v-if="hasFooterSlot">
            <slot name="footer"></slot>
        </div>
    </div>
</template>

Script

<script>
    export default {
        props: {
            active: true,
            type: {
                type: String,
                default: 'default',
            },
        },

        computed: {
            panelType() {
                return `panel-${this.type}`;
            },

            hasFooterSlot() {
                return this.$slots['footer']
            }
        }
    }
</script>

In in View:

<card type="success"></card>

Since the above component doesn't contain a footer, it should not be rendered, but it is.

I've tried using this.$slots['footer'], but this returns undefined.

Does anyone have any tips?

vuejs2 vue.js
13 Answers

You should check vm.$slots and also vm.$scopedSlots for it.

hasSlot (name = 'default') {
   return !!this.$slots[ name ] || !!this.$scopedSlots[ name ];
}
user_91671160

CSS simplifies this a lot. Just use the following code and voila!

.panel-footer:empty {
  display: none;
}
user_2175270

This is the solution for Vue 3 composition API:

<template>
    <div class="md:grid md:grid-cols-5 md:gap-6">

        <!-- Here, you hide the wrapper if there is no used slot or empty --> 
        <div class="md:col-span-2" v-if="hasTitle">
            <slot name="title"></slot>
        </div>

        <div class="mt-5 md:mt-0" 
            :class="{'md:col-span-3': hasTitle, 'md:col-span-5': !hasTitle}">
            <div class="bg-white rounded-md shadow">
                <div class="py-7">
                    <slot></slot>
                </div>
            </div>
        </div>
    </div>
</template>

<script>
import {ref} from "vue";

export default {
    setup(props, {slots}) {
        const hasTitle = ref(false)

        // Check if the slot exists by name and has content.
        // It returns an empty array if it's empty.
        if (slots.title && slots.title().length) {
            hasTitle.value = true
        }

        return {
            hasTitle
        }
    }
}
</script>
user_40863960

In short do this in inline:

<template lang="pug">
  div
    h2(v-if="$slots.title")
      slot(name="title")
    h3(v-if="$slots['sub-title']")
      slot(name="sub-title")
</template>
user_12920500

I have ran into a similiar issue but across a wide code base and when creating atomic design structured components it can be tiring writing hasSlot() methods all the time and when it comes to TDD - its one more method to test... Saying that, you can always put the raw logic in a v-if but i have found that the template end up cluttered and harder to read on occasions especially for a new dev checking out the code structure.

I was tasked to find out a way of removing parent divs of slots when the slot isnt provided.

Issue:

<template>
  <div>
    <div class="hello">
      <slot name="foo" />
    </div>
    <div class="world">
      <slot name="bar" />
    </div>
  </div>
</template>

//instantiation
<my-component>
  <span slot="foo">show me</span>
</my-component>

//renders
<div>
  <div class="hello">
    <span slot="foo">show me</span>
  </div>
  <div class="world"></div>
</div>

as you can see, the issue is that i have an almost 'trailing' div, that could provide styling issues when the component author decides there is no need for a bar slot.

ofcourse we could go <div v-if="$slots.bar">...</div> or <div v-if="hasBar()">...</div> etc but like i said - that can get tiresome and eventually end up harder to read.

Solution

My solution was to make a generic slot component that just rendered out a slot with a surrounding div...see below.

//slot component
<template>
  <div v-if="!!$slots.default">
    <slot />
  </div>
</template>


//usage within <my-component/>
<template>
  <div>
    <slot-component class="hello">
      <slot name="foo"/>
    </slot-component>
    <slot-component class="world">
      <slot name="bar"/>
    </slot-component>
  </div>
</template>

//instantiation
<my-component>
  <span slot="foo">show me</span>
</my-component>

//renders
<div>
  <div class="hello">
    <span>show me</span>
  </div>
</div>

I came into use-case issues when trying this idea and sometimes it was my markup structure that needed to change for the benefit of this approach. This approach reduces the need for small slot checks within each component template. i suppose you could see the component as a <conditional-div /> component...

It is also worth noting that applying attributes to the slot-component instantiation (<slot-component class="myClass" data-random="randomshjhsa" />) is fine as the attributes trickle into the containing div of the slot-component template.

Hope this helps.

UPDATE I wrote a plugin for this so the need for importing the custom-slot component in each consumer component is not needed anymore and you will only have to write Vue.use(SlotPlugin) in your main.js instantiation. (see below)

const SLOT_COMPONENT = {
  name: 'custom-slot',
  template: `
    <div v-if="$slots.default">
      <slot />
    </div>
  `
}

const SLOT_PLUGIN = {
  install (Vue) {
    Vue.component(SLOT_COMPONENT.name, SLOT_COMPONENT)
  }
}

export default SLOT_PLUGIN

//main.js
import SlotPlugin from 'path/to/plugin'
Vue.use(SlotPlugin)
//...rest of code

user_68654160

Now, in Vue3 composition API , you can use useSlots.

<script setup>
const slots = useSlots()
</script>

<template>
  <div v-if="slots.content" class="classname">
    <slot name="content"></slot>
  </div>
</template>
user_191496480

Initially I thought https://stackoverflow.com/a/50096300/752916 was working, but I had to expand on it a bit since $scopeSlots returns a function which is always truthy regardless of its return value. This is my solution, though I've come to the conclusion that the real answer to this question is "doing this is an antipattern and you should avoid it if possible". E.g. just make a separate footer component that could be slotted in.

Hacky solution

   hasFooterSlot() {
        const ss = this.$scopedSlots;
        const footerNodes = ss && ss.footer && ss.footer();
        return footerNodes && footerNodes.length;
   }

Best Practice (helper component for footer)

const panelComponent = {
  template: `
    <div class="nice-panel">
        <div class="nice-panel-content">
          <!-- Slot for main content -->
          <slot />
        </div>
        <!-- Slot for optional footer -->
        <slot name="footer"></slot>
    </div>
  `
}
const footerComponent = {
  template: `
    <div class="nice-panel-footer">
        <slot />
    </div>
  `
}

var app = new Vue({
  el: '#app',
  components: {
    panelComponent,
    footerComponent
  },
  data() {
    return {
      name: 'Vue'
    }
  }
})
.nice-panel {
  max-width: 200px;
  border: 1px solid lightgray;
}

.nice-panel-content {
  padding: 30px;
}

.nice-panel-footer {
  background-color: lightgray;
  padding: 5px 30px;
  text-align: center;
}
<script src="https://unpkg.com/vue@2.6.11/dist/vue.min.js"></script>
<div id="app">
  <h1>Panel with footer</h1>

  <panel-component>
    lorem ipsum
    <template #footer>
      <footer-component> Some Footer Content</footer-component>
    </template>
  </panel-component>

  <h1>Panel without footer</h1>

  <panel-component>
    lorem ipsum
  </panel-component>
</div>

user_7529160

Hope I understand this right. Why not using a <template> tag, which is not rendered, if the slot is empty.

<slot name="foo"></slot>

Use it like this:

<template slot="foo">
   ...
</template>
user_17878870

TESTED

So this work for me in vue 3:

I use onMounted to first get the value, and then onUpdate so the value can update.

   <template>
     <div v-if="content" class="w-1/2">
          <slot name="content"></slot>
     </div>
   </template>


 <script>
     import { ref, onMounted, defineComponent, onUpdated } from "vue";   
     export default defineComponent({
        setup(props, { slots }) {
        const content = ref()
        onMounted(() => {
                if (slots.content && slots.content().length) {
                    content.value = true
                }
            })
            onUpdated(() => {
                content.value = slots.content().length
                console.log('CHECK VALUE', content.value)
            })
})
</script>
user_122375050

@Bert answer does not seem to work for dynamic templates like <template v-slot:foo="{data}"> ... </template>. i ended up using:

 return (
        Boolean(this.$slots.foo) ||
        Boolean(typeof this.$scopedSlots.foo == 'function')
      );
user_17615880

I like the Solution of @AlexMA however in my case I needed to pass props to the function in order to get the nodes to show up.

Here is an example of how I am passing the "row" to the scoped slot, in my case the row contains a type param that I want to test against in the calling component.

<other-component>
    <template v-slot:expand="{ row }" v-if="!survey.editable">
        <div v-if="row.type != 1" class="flex">
            {{ row }}
        </div>
    </template>
</other-component>

In "other-component" I have the template defined as

<template>
    <div>
        <div v-for="(row, index) in rows">
            {{ hasSlotContent(row) }}
            <slot name="expand" :row="row"> </slot>
        </div>
    </div>
</template>

Because the v-slot requires "row" to be passed to it I created a a method

methods:{
    hasSlotContent(row){
        const ss = this.$scopedSlots
        const nodes = ss && ss.expand && ss.expand({ row: row })
        return !!(nodes && nodes.length)
    }
}

I call this on each iteration so that it can evaluate itself and give back the appropriate response. you can use the "hasSlotContent(row)" method where-ever you need it, in my example I'm just outputting the truthy value to the DOM.

I hope this helps someone come to a quicker solution.

user_95328290

For Vue 3:

Create an utility function

    //utils.js
    function isSlotHasContent(slotName, slots) {
      return Boolean(!!slots[slotName] && slots[slotName]()[0].children.length > 0);
    }

In your component:

    <script setup>
      import { isSlotHasContent } from 'path/to/utils.js';

      const slots = useSlots();

      // "computed" props has a better performance
      const isFooSlotHasContent = computed(() => isSlotHasContent('foo', slots));
    </script>

    <template>
      <div>
        <div v-if="isFooSlotHasContent">
          <slot name="foo" />
        </div>
        <div v-if="!isFooSlotHasContent">
          Some placeholder
        </div>
      </div>
    </template>
user_162804290
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