I'm trying to rewrite code from Haskell to Prolog.
count :: Eq a => a -> [a] -> Int
count x = length . filter (x==)
f :: [Integer] -> [Integer]
f [] = []
f list = filter (\x -> count x list == 1) list
This code return list that contains elements that appears only once in the list.
So if I have list [1,1,2,2,3,4,4,5] this function returns [3,5]
I tried to find filter construction in Prolog but seems there no such thing. How can I make similar function in Prolog ?