Idiomatic Revealing Module Pattern for ES6

In the past I've used the revealing module pattern.

function myModule() {
  function foo() ...
  function bar() ...

  return { 
    foo: foo, 
    bar: bar
  };
}

With ES6, this was improved with object shorthand.

function myModule() {
  function foo() ...
  function bar() ...

  return { foo, bar };
}

Now with built-in module syntax, I'm struggling to find the preferred pattern that is most similar to the above.

Option #1 named exports

// export file
function foo() ...
function bar() ...

export { foo, bar };

// import file
import { foo, bar } from './export-file';

foo();
bar();

Option #2 default export/import with destructuring

// export file
function foo() ...
function bar() ...

export default { foo, bar };

// import file
import baz from './export-file';

const { foo, bar } = baz;

foo();
bar();

Option #3 default export/import with name spacing

// export file
function foo() ...
function bar() ...

export default { foo, bar };

//import file
import baz from './export-file';

baz.foo();
baz.bar();

I like Option #1 with the named exports for the simplicity it offers in the "destructuring" import syntax.

import { foo, bar } from './export-file';

I also want to continue to make the module's exported API explicitly defined at the bottom of the exporting file in the export object.

export { foo, bar };
// OR
export default { foo, bar };

I read all the time that default exports are preferred, and so I've been trying to find a preferred pattern that includes default exports, but I'm reluctant to adopt as it just seems more verbose with few advantages (other than the need for name-spacing, or the inclusion of both named and default exports in some cases).

Is there an idiomatic pattern for the revealing module pattern with ES6 module syntax?