awk command to print multiple columns using for loop

I am having a single file in which it contains 1st and 2nd column with item code and name, then from 3rd to 12th column which contains its 10 days consumption quantity continuously. Now i need to convert that into 10 different files. In each the 1st and 2nd column should be the same item code and item name and the 3rd column will contain the consumption quantity of one day in each..

input file:

Code  | Name | Day1 | Day2 | Day3 |... 

10001 | abcd | 5 | 1 | 9 |...    
10002 | degg | 3 | 9 | 6 |...    
10003 | gxyz | 4 | 8 | 7 |...

I need the Output in different file as

file 1:

Code  | Name | Day1

10001 | abcd | 5   
10002 | degg | 3   
10003 | gxyz | 4   

file 2:

Code  | Name | Day2

10001 | abcd | 1   
10002 | degg | 9   
10003 | gxyz | 8  

file 3:

Code  | Name | Day3

10001 | abcd | 9   
10002 | degg | 6   
10003 | gxyz | 7 

and so on....

I wrote a code like this

awk 'BEGIN { FS = "\t" } ; {print $1,$2,$3}' FILE_NAME > file1;
awk 'BEGIN { FS = "\t" } ; {print $1,$2,$4}' FILE_NAME > file2;
awk 'BEGIN { FS = "\t" } ; {print $1,$2,$5}' FILE_NAME > file3;

and so on...

Now i need to write it with in a 'for' or 'while' loop which would be faster...

I dont know the exact code, may be like this..

for (( i=3; i<=NF; i++)) ; do awk 'BEGIN { FS = "\t" } ; {print $1,$2,$i}' input.tsv > $i.tsv; done

kindly help me to get the output as i explained.