WKWebView open links from certain domain in safari

user_5819330 0
Viewed 67046

Within my app I am want to open links from within my domain (e.g.: communionchapelefca.org) in WKWebView but then have links from other domains open in Safari. I would prefer to do this programmatically.

I have found a few solutions on Stack overflow (here, here, here, and here) but they all seem to be Obj-C based and I am looking for a solution using Swift.

ViewController.swift:

import UIKit
import WebKit

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
        
        let myWebView:WKWebView = WKWebView(frame: CGRectMake(0, 0,   UIScreen.mainScreen().bounds.width, UIScreen.mainScreen().bounds.height))
        
        myWebView.loadRequest(NSURLRequest(URL: NSURL(string: "http://www.communionchapelefca.org/app-home")!))
        
        self.view.addSubview(myWebView)
wkwebview swift safari ios
7 Answers

For Swift 3.0

import UIKit
import WebKit

class ViewController: UIViewController, WKNavigationDelegate {
    let wv = WKWebView(frame: UIScreen.main.bounds)
    override func viewDidLoad() {
        super.viewDidLoad()
        guard let url =  NSURL(string: "https://www.google.com") else { return }
        wv.navigationDelegate = self
        wv.load(NSURLRequest(url: url as URL) as URLRequest)
        view.addSubview(wv)
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

    func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
        if navigationAction.navigationType == .LinkActivated  {
            if let newURL = navigationAction.request.url,
                let host = newURL.host , !host.hasPrefix("www.google.com") &&
                UIApplication.shared.canOpenURL(newURL) &&
                UIApplication.shared.openURL(newURL) {
                    print(newURL)
                    print("Redirected to browser. No need to open it locally")
                    decisionHandler(.cancel)
            } else {
                print("Open it locally")
                decisionHandler(.allow)
            }
        } else {
            print("not a user click")
            decisionHandler(.allow)
        }
    }
}
user_19469130

Swift 4 update for George Vardikos answer:

public func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
        let url = navigationAction.request.url
        guard url != nil else {
            decisionHandler(.allow)
            return
        }

        if url!.description.lowercased().starts(with: "http://") ||
            url!.description.lowercased().starts(with: "https://")  {
            decisionHandler(.cancel)
            UIApplication.shared.open(url!, options: [:], completionHandler: nil)
        } else {
            decisionHandler(.allow)
        }
}
user_109291680

Swift 5 and iOS >10

Don't use UIApplication.shared.openURL(url!), it's deprecated. We use UIApplication.shared.open(url!) instead.

 public func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
        
        guard let url = navigationAction.request.url else{
            decisionHandler(.allow)
            return
        }
        
        let urlString = url.absoluteString.lowercased()
        if urlString.starts(with: "http://") || urlString.starts(with: "https://") {
            decisionHandler(.cancel)
            UIApplication.shared.open(url, options: [:])
        } else {
            decisionHandler(.allow)
        }
        
    }
user_9273330
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