Type Has No Subscript Members?

user_488274 0
Viewed 45174

I get the error "Type 'Ship' has no subscript members when I try to do:

var coor = ship[index]

I tried to do

var coor = ship?[index] as? Coordinate

But I get this error: "Cannot use optional chaining on non-optional value of type 'Ship'"

Here's my Ship class:

import Foundation

class Ship: NSObject, NSCoding {

    var shipCoors: [Coordinate]?

    var count: Int {
        var count = 0
        for _ in shipCoors! {
            count++
        }
        return count
    }

    init(shipCoors: [Coordinate]) {
        self.shipCoors = shipCoors
    }

    required init(coder decoder: NSCoder) {
        self.shipCoors = decoder.decodeObjectForKey("shipCoors") as? [Coordinate]
    }

    func encodeWithCoder(coder: NSCoder) {
        coder.encodeObject(shipCoors, forKey: "shipCoors")
    }
}

The Coordinate class is also of type NSObject, NSCoding, etc... The objects seem to be in the array when I load them (from NSUserDefaults)? How do I get them out?!

subscript option-type nscoding swift ios
4 Answers

Had similar issue in Swift 3

Type '() -> [myObject]' has no subscript members

In my case, It was a simple case of not adding the brackets to the function-call "()". school boy error.

i.e. the below code was the culprit

dataModel.myFunction

Solved with dataModel.myFunction()

user_54382400

For my code:

func takeN(_ numbers: Int...) -> [Int]{
    var intArray : [Int] = []
    for n in numbers{
        intArray.append[n]

    }
    return intArray
}

I was getting the following error:

error: type '(Int) -> ()' has no subscript members intArray.append[n]

It means the append function doesn't use subscripts or []!

changing the line of 

intArray.append[n]

to:

intArray.append(n)

would resolve the entire issue!

user_51757090
Related