I need to force the class to implement some method for example onCreate(), as in other languages like php we can see something like:
<?php
// Declare the interface 'Movement'
interface MovementEvents
{
public function onWalk($distance);
}
// Declare the abstract class 'Animal'
abstract class Animal implements MovementEvents{
protected $energy = 100;
public function useEnergy($amount){
$energy -= $amount;
}
}
class Cat extends Animal{
// If I didn't implement `onWalk()` I will get an error
public function onWalk($distance){
$amount = $distance/100;
$this->useEnergy($amount)
}
}
?>
Note that in my example if I didn't implement onWalk() the code will not work and you will get an error but when I do the same in TypeScript as following:
// Declare the interface 'Movement'
interface MovementEvents
{
onWalk: (distance)=>number;
}
// Declare the abstract class 'Animal'
abstract class Animal implements MovementEvents{
protected energy:number = 100;
public useEnergy(amount:number):number{
return this.energy -= amount;
}
}
class Cat extends Animal{
// If I didnt implment `onWalk()` I will get an error
public onWalk(distance:number):number{
var amount:number = distance/100;
return this.useEnergy(amount);
}
}
No error will show whether I did or didn't implement the on walk method but the it will give an error if I didn't implement onWalk() in the Animal class, I need to have same as php in TypeScript?