How to call a function with a dictionary that contains more items than the function has parameters?

I am looking for the best way to combine a function with a dictionary that contains more items than the function's inputs

basic **kwarg unpacking fails in this case:

def foo(a,b):
    return a + b

d = {'a':1,
     'b':2,
     'c':3}

foo(**d)
--> TypeError: foo() got an unexpected keyword argument 'c'

After some research I came up with the following approach:

import inspect

# utilities
def get_input_names(function):
    '''get arguments names from function'''
    return inspect.getargspec(function)[0]

def filter_dict(dict_,keys):
    return {k:dict_[k] for k in keys}

def combine(function,dict_):
    '''combine a function with a dictionary that may contain more items than the function's inputs '''
    filtered_dict = filter_dict(dict_,get_input_names(function))
    return function(**filtered_dict)

# examples
def foo(a,b):
    return a + b

d = {'a':1,
     'b':2,
     'c':3}

print combine(foo,d)
--> 3

My question is: is this a good way of dealing with this problem, or is there a better practice or is there a mechanism in the language that I'm missing perhaps?