Grab unique tuples in python list, irrespective of order

user_3834415 0
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I have a python list:

[ (2,2),(2,3),(1,4),(2,2), etc...]

What I need is some kind of function that reduces it to its unique components... which would be, in the above list:

[ (2,2),(2,3),(1,4) ]

numpy unique does not quite do this. I can think of a way to do it--convert my tuples to numbers, [22,23,14,etc.], find the uniques, and work back from there...but I don't know if the complexity won't get out of hand. Is there a function that will do what I am trying to do with tuples?

Here is a sample of code that demonstrates the problem:

 import numpy as np

 x = [(2,2),(2,2),(2,3)]
 y = np.unique(x)

returns: y: [2 3]

And here is the implementation of the solution that demonstrates the fix:

 x = [(2,2),(2,2),(2,3)]
 y = list(set(x))

returns y: [(2,2),(2,3)]

duplicates list numpy python
4 Answers

you could simply do 

y = np.unique(x, axis=0)
z = [] 
for i in y:
   z.append(tuple(i))

The reason is that a list of tuples is interpreted by numpy as a 2D array. By setting axis=0, you'd be asking numpy not to flatten the array and return unique rows.

user_62935860
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