System out println

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I'm printing 2 lines to the console. They both print, but when the second one has printed, the first one changes to the second one, so the 2 lines are identical. I've never encountered this before. Why does the second print overwrite the first one, and how do I fix it?

public static void main(String args[]){
    new MergeSort(90000);

    System.out.println("Array to be mergesorted: " +Arrays.toString(array));

    long start = System.currentTimeMillis();

    mergeSort(array, 1, array.length);

    long end = System.currentTimeMillis();

    System.out.println("Result: " + Arrays.toString(array) );
}

The constructor:

public MergeSort(int n){
    Random rand = new Random();
    array = new int[n];
    for(int i = 0; i <array.length; i++){
        array[i] = rand.nextInt(101);
    }
}

Rest of code:

public static void merge(int[] A, int p, int q, int r){
    //
    //length of subarray 1
    int n1 = q-p+1;

    //length of subarray 2
    int n2 = r-q;

    int[] L = new int[n1+1];
    int[] R = new int[n2+1];

    for(int i = 0; i < n1; i++){
        L[i] = A[p+i-1];
    }

    for(int j=0; j< n2; j++){
        R[j] = A[q+j];
    }

    L[n1] = Integer.MAX_VALUE;
    R[n2] = Integer.MAX_VALUE;

    int i = 0;
    int j = 0;

    for(int k = p-1; k < r; k++){
        if(L[i] <= R[j]){
            A[k] = L[i];
            i++;
        }
        else{
                A[k] = R[j];
                j++;
            }
    }

}

public static void mergeSort(int[] A, int p, int r){
    if (p<r){
        int q = (int) Math.floor((r+p)/2);
        mergeSort(A, p, q);
        mergeSort(A, q+1, r);
        merge(A, p, q, r);
    }
}
1 Answers
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