Initialize/set char *argv[] inside main() in one line

I want to initialize/set char *argv[] inside the main() so that I can use argv[1], argv[2]... later in my program.

Up to now, I know how to do this in two ways:

1. For int main(), use one line as:

   int main()
   {
       char *argv[] = {"programName", "para1", "para2", "para3", NULL};
   }
   

   Note that, using NULL in the end is because the pointers in the argv array point to C strings, which are by definition NULL terminated.

2. For int main(int argc, char* argv[]), I have to use multiple lines as:

   int main(int argc,char* argv[])
   {
       argv[0] = "programName";
       argv[1] = "para1";
       argv[2] = "para2";
       argv[3] = "para3";
   }
   

My question is that how can I combine these two methods together, i.e. use only one line to initialize it for int main(int argc, char* argv[])? Particularly, I want to be able to do like this (this will be wrong currently):

int main(int argc, char* argv[])
{
    argv = {"programName", "para1", "para2", "para3", NULL};
}

How can I be able to do this?

Edit: I know argv[] can be set in Debugging Command Arguments. The reason that I want to edit them in main() is that I don't want to bother to use Debugging Command Arguments every time for a new test case (different argv[] setting).