Open Settings app from another app programmatically in iPhone

user_1812422 0
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I have to open settings app from my app if gps is not enabled in iPhone. I have used the following code. It works well in iOS simulator but it does not work in iPhone. May I know is there any problem in this code. 

if (![CLLocationManager locationServicesEnabled]) {
        int (*openApp)(CFStringRef, Boolean);
        void *hndl = dlopen("/System/Library/PrivateFrameworks/SpringBoardServices.framework/SpringBoardServices");
        openApp = (int(*)(CFStringRef, Boolean)) dlsym(hndl, "SBSLaunchApplicationWithIdentifier");
        openApp(CFSTR("com.apple.Preferences"), FALSE);
        dlclose(hndl);
    }
gps settings iphone ios
6 Answers

openURL was deprecated in iOS10.0: Please use openURL:options:completionHandler instead

let url = URL(string: UIApplicationOpenSettingsURLString)!
UIApplication.shared.open(url, options: [:]) { success in }
user_6691190
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