Pointers and Strings C++

I'm teaching myself C++ and I'm a bit confused about pointers (specifically in the following source code). But first, I proceed with showing you what I know (and then contrasting the code against this because I feel as if there are some contradictions going on).

What I know:

int Age = 30;
int* pointer = &Age;

cout << "The location of variable Age is: " << pointer << endl;
cout << "The value stored in this location is: " << *pointer << endl;

Pointers hold memory addresses. Using the indirection (dereference) operator (the *), you can access what is stored in memory location of the pointer. Onto the code in this book I'm having trouble understanding...

cout << "Enter your name: ";
string name;
getline(cin, name); //gets full line up to NULL terminating character

int CharsToAllocate = name.length() + 1; //calculates length of string input
                          //adds one onto it to adjust for NULL character
char* CopyOfName = new char[CharsToAllocate];
// pointer to char's called CopyOfName, is given the memory address of the 
//beginning of a block
//of memory enough to fit CharsToAllocate. Why we added 1? Because char's need a 
//NULL terminating character (\0)

strcpy(CopyOfName, name.c_str()); //copies the string name, into a pointer?

cout << "Dynamically allocated buffer contains: " << CopyOfName << endl;
delete[] CopyOfName; //always delete a pointer assigned by new to prevent memory leaks

Output:

Enter your name: Adam
Dynamically allocated buffer contains: Adam

The comments in the above code are my comments. My problem begins with strcpy. Why is name.c_str() copied into a pointer CopyOfName? Does this mean that all strings are essential pointers? So like string testing = "Hello world"; Is actually a pointer pointing to the memory location where "H" is stored?

Next, why is it in the print out statement using CopyOfName and not *CopyOfName? Pointers hold memory addresses? Using *CopyOfName would print out the contents of the memory location. I tried this in Code::Blocks and if the input text was "Hello World." Using *CopyOfName in the print out statement would just give an "H". This makes sense since when I declared that I needed a memory block with the 'new' thing, this actually returns a pointer to the first part of the dynamically allocated memory block.

The only way I can reconcile this is if a string is actually a pointer.

string testing = "Confused";
cout << testing << endl;

would print out the word "Confused"

However, if I try to compile

string testing = "Confused";
cout << *testing; 

I get an error message.

Basically, to summarize my question, I'm trying to understand the code with strcpy and the cout statement.