I have two separate handfuls of REST services in one application. Let's say a main "people" service and a secondary "management" service. What I want is to expose them in separate paths on the server. I am using JAX-RS, RESTEasy and Spring.
Example:
@Path("/people")
public interface PeopleService {
// Stuff
}
@Path("/management")
public interface ManagementService {
// Stuff
}
In web.xml I currently have the following set-up:
<listener>
<listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>
<listener>
<listener-class>org.jboss.resteasy.plugins.spring.SpringContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/public</param-value>
</context-param>
<servlet>
<servlet-name>Resteasy</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Resteasy</servlet-name>
<url-pattern>/public/*</url-pattern>
</servlet-mapping>
The PeopleService and ManagementService implementations are just Spring beans.
Above web.xml configuration will expose them both on /public (so having /public/people and /public/management respectively).
What I want to accomplish is to expose the PeopleService on /public, so that the full path would become /public/people and expose the ManagementService on /internal, so that its full path would become /internal/management.
Unfortunately, I cannot change the value of the @Path annotation.
How should I do that?