Using MINLOC with Fortran: Incompatible ranks 0 and 1 in assignment

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Version that gives an error message

program hello
   integer a(9)
   integer index; ! note no dimension here
   a=(/1, 3, 4, 5, 6, 7, 8, 9, 10/)
   index = MINLOC(a, MASK=(a > 5))
   Print *, index
end program Hello

Error message

main.f95:5.3:

index = MINLOC(a, MASK=(a > 5)) 1 Error: Incompatible ranks 0 and 1 in assignment at (1)

Working version

program hello
   integer a(9)
   integer index(1) ! note dimension 1 here which looks redundant at first
   a=(/1, 3, 4, 5, 6, 7, 8, 9, 10/)
   index = MINLOC(a, MASK=(a > 5))
   Print *, index
end program Hello

Search

Here I could find related discussion but I don't find it sufficiently verbose for me to understand the difference.

2 Answers
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