I'm using GNU/MIT Scheme:
1 ]=> (+)
;Value: 0
1 ]=> (*)
;Value: 1
1 ]=> (-)
;The procedure #[arity-dispatched-procedure 2] has been called with 0 arguments; it requires at least 1 argument.
;To continue, call RESTART with an option number:
; (RESTART 1) => Return to read-eval-print level 1.
2 error> (/)
;The procedure #[arity-dispatched-procedure 3] has been called with 0 arguments; it requires at least 1 argument.
;To continue, call RESTART with an option number:
; (RESTART 2) => Return to read-eval-print level 2.
; (RESTART 1) => Return to read-eval-print level 1.
How come + and * are both evaluated to 0 and 1 respectively. And why evaluating - and / throws an error?
Is this part of the Scheme definition or is it an implementation detail in GNU/MIT Scheme?