how to get the full path name to an exception so I can add an exception handler

I want to catch an exception, but I don't know its fully qualified name. I would like to figure it out experimentally without digging thru documentation.

Let's say I have code that looks like this

try:
   blackbox()
except Exception,e:
   print str(e)
   print e.__class__.__name__

And it runs and I get an exception message that says

"error: too big"
error

So I add a handler

try:
   blackbox()
except error,e:
   pass
except Exception,e:
   print str(e)
   print e.__class__.__name__

but it doesn't work, because error is not in the current namespace. (I know the answer to this particular question, it happens to be curses.error). How I figure out the namespace of an exception object (i.e. curses. so I can add a handler for that exception?