Truncate a decimal value in Python

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I am trying to truncate a decimal value in Python. I don't want to round it, but instead just display the decimal values upto the specified accuracy. I tried the following:

d = 0.989434
'{:.{prec}f}'.format(d, prec=2)

This rounds it to 0.99. But I actually want the output to be 0.98. Obviously, round() is not an option. Is there any way to do this? Or should I go back to the code and change everything to decimal?

Thanks.

truncate decimal formatting python
12 Answers

In this link here I posted the solution below:

def truncate_number(f_number, n_decimals):
      strFormNum = "{0:." + str(n_decimals+5) + "f}"
      trunc_num = float(strFormNum.format(f_number)[:-5])
      return(trunc_num)

# Testing the 'trunc_num()' function
test_num = 1150/252
[(idx, truncate_number(test_num, idx)) for idx in range(0, 20)]

At leat it doesn't require to load any module nor demands new calculations. So far, it solved my problem with the truncation requirements in public bond prices calculations.

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