${str?replace("\d+", "", "r")};
I wanted to use \d to remove numbers, but it didn't work!!!
But ${str?replace("[0-9]", "", "r")}; works!!!
So, I wanna know how to use regex like \d, \b, \w, etc?
${str?replace("\d+", "", "r")};
I wanted to use \d to remove numbers, but it didn't work!!!
But ${str?replace("[0-9]", "", "r")}; works!!!
So, I wanna know how to use regex like \d, \b, \w, etc?
You need to double the backslashes:
${str?replace("\\d+", "", "r")};
This is because string escaping rules are applied before regex escaping rules. So the string "\\d" is translated to the regex \d which then matches a digit.
If your string is "\d", the string processor translates it to a literal d (because \d is not a recognized string escape sequence, so it's ignored).