How can I get a count of the number of arguments to a variadic template function?
ie:
template<typename... T>
void f(const T&... t)
{
int n = number_of_args(t);
...
}
What is the best way to implement number_of_args in the above?
C++11: Number of Variadic Template Function Parameters?
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2 Answers
#include <iostream>
template<typename ...Args>
struct SomeStruct
{
static const int size = sizeof...(Args);
};
template<typename... T>
void f(const T&... t)
{
// this is first way to get the number of arguments
constexpr auto size = sizeof...(T);
std::cout<<size <<std::endl;
}
int main ()
{
f("Raje", 2, 4, "ASH");
// this is 2nd way to get the number of arguments
std::cout<<SomeStruct<int, std::string>::size<<std::endl;
return 0;
}
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