How to list the source table name of columns in a VIEW (SQL Server 2005)

user_1596913 0
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Just wondering how to list column name and table name in one query for a view.

For example:

A view named as viewC, create by tbl1 inner join tbl2, contain a,b,c,d columns (a,b from tbl1 and c,d from tbl2).

How to 

Select COLUMN_NAME, DATA_TYPE, column_default, character_maximum_length, sourceTableNAME 
FROM information_schema.columns 
where table_name='viewC'

together?

sql-server-2005 view tsql sql
3 Answers

I had a view (SQL Server 2012) that read from another database and had a UNION as well. The above queries didn't work for me, so I decided to use the Profiler to check how SSMS would retrieve the information. This is what I ended up with:

SELECT
     clmns.name AS [Name]
    ,usrt.name AS [DataType]
    ,CAST(CASE WHEN baset.name IN (N'nchar', N'nvarchar') AND clmns.max_length <> -1 THEN clmns.max_length/2 ELSE clmns.max_length END AS int) AS [Length]
    ,CAST(clmns.precision AS int) AS [NumericPrecision]
    ,CAST(clmns.scale AS int) AS [NumericScale]
    ,clmns.column_id AS [ID]
FROM    sys.all_views AS v
INNER JOIN sys.all_columns AS clmns 
    ON clmns.object_id=v.object_id
LEFT OUTER JOIN sys.indexes AS ik 
    ON ik.object_id = clmns.object_id 
    AND 1=ik.is_primary_key
LEFT OUTER JOIN sys.types AS usrt 
    ON usrt.user_type_id = clmns.user_type_id
LEFT OUTER JOIN sys.types AS baset
    ON (baset.user_type_id = clmns.system_type_id AND baset.user_type_id = baset.system_type_id) 
    OR ((baset.system_type_id = clmns.system_type_id) AND (baset.user_type_id = clmns.user_type_id) AND (baset.is_user_defined = 0) AND (baset.is_assembly_type = 1)) 
LEFT OUTER JOIN sys.xml_schema_collections AS xscclmns
    ON xscclmns.xml_collection_id = clmns.xml_collection_id
WHERE v.[type] = 'V'
    AND  v.name ='<your view name>' 
    AND SCHEMA_NAME(v.schema_id)='<your schema name>'
ORDER BY [ID] ASC
user_9802010
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