copy a directory structure with file names without content

user_463676 0
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I have a huge directory structure of movie files. For analysis of that structure I want to copy the entire directory structure, i.e. folders and files however I don't want to copy all the movie files while I want to keep there file names. Ideally I get zero-byte files with the original movie file name.

I tried to and then rsync to my remote machine which didn't fetch the link files.

Any ideas how to do that w/o writing scripts?

structure copy rsync linux
4 Answers

I needed an alternative to this to sync only the file structure:

rsync --recursive --times --delete --omit-dir-times --itemize-changes "$src_path/" "$dst_path"

This is how I realized it:

# sync source to destination
while IFS= read -r -d '' src_file; do
  dst_file="$dst_path${src_file/$src_path/}"
  # new files
  if [[ ! -e "$dst_file" ]]; then
    if [[ -d "$src_file" ]]; then
      mkdir -p "$dst_file"
    elif [[ -f $src_file ]]; then
      touch -r "$src_file" "$dst_file"
    else
      echo "Error: $src_file is not a dir or file"
    fi
    echo -n "+ "
    ls -ld "$src_file"
  # modification time changed (files only)
  elif [[ -f $dst_file ]] && [[ $(date -r "$src_file") != $(date -r "$dst_file") ]]; then
    touch -r "$src_file" "$dst_file"
    echo -n "+ "
    ls -ld "$src_file"
  fi
done < <(find "$src_path" -print0)

# delete files in destination if they disappeared in source
while IFS= read -r -d '' dst_file; do
  src_file="$src_path${dst_file/$dst_path/}"
  # file disappeard on source
  if [[ ! -e "$src_file" ]]; then
    delinfo=$(ls -ld "$dst_file")
    if [[ -d "$dst_file" ]] && rmdir "$dst_file" 2>/dev/null; then
      echo -n "- $delinfo"
    elif [[ -f $dst_file ]] && rm "$dst_file"; then
      echo -n "- $delinfo"
    fi
  fi
done < <(find "$dst_path" -print0)

As you can see I use echo and ls to display changes.

user_3187650
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