Do I still get default copy constructor and operator= if I define ones with non-const arguments?

In C++, if I define a copy constructor and operator= that take a non-const reference to the class, is the compiler supposed to still supply default versions for const reference?

struct Test {
  Test(Test &rhs);
  Test &operator=(Test &rhs);

private:
  // Do I still need to declare these to avoid automatic definitions?
  Test(const Test &rhs);
  Test &operator=(const Test &rhs);
};