Iterating in R to spell check a vector of words

I have a data set that is full of inappropriately spaced sentences. I'm trying to come up with a way to remove some of the spaces.

I start with a sentence that I convert to a data frame of words:

> word5 <- "hotter the doghou se would be bec ause the co lor was diffe rent"
> abc1 <- data.frame(filler1 = 1,words1=factor(unlist(strsplit(word5, split=" "))))
> abc1
   filler1 words1
1        1 hotter
2        1    the
3        1 doghou
4        1     se
5        1  would
6        1     be
7        1    bec
8        1   ause
9        1    the
10       1     co
11       1    lor
12       1    was
13       1  diffe
14       1   rent

Next I use the following code to try and spell check and combine words that are the combination of the word before or after them:

abc2 <- abc1
i <- 1
while(i < nrow(abc1)){
  print(abc2)
  if(nrow(aspell(abc1$words1[i])) == 0){
    print(paste(i,"Words OK",sep=" | "));flush.console() 
    i <- i + 1
  }
 else{
  if(nrow(aspell(abc1$words1[i])) > 0 & i != 1){
    preWord1 <- abc1$words1[i-1]
    postWord1 <- abc1$words1[i+1]
    badWord1 <- abc1$words1[i]
    newWord1 <- factor(paste(preWord1,badWord1,sep=""))
    newWord2 <- factor(paste(badWord1,postWord1,sep=""))

    if(nrow(aspell(newWord1)) == 0 & nrow(aspell(newWord2)) != 0){
      abc2[i,"words1"] <-as.character(newWord1)
      abc2 <- abc2[-c(i+1),]
      print(paste(i,"word1",sep=" | "));flush.console()
      i <- i + 1
    }

    if(nrow(aspell(newWord1)) != 0 & nrow(aspell(newWord2)) == 0){
      abc2[i ,"words1"] <-as.character(newWord2)
      abc2 <- abc2[-c(i-1),]
      print(paste(i,"word2",sep=" | "));flush.console()
      i <- i + 1
    }

  }
}
}

After playing with this for sometime I'm coming to the conclusion that I need some type of iterator but am uncertain of how to implement it in R. Any suggestions?