Time discrete implementation of 1st order RC filter

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I'm trying to make sure I understand my (digital) signal processing knowledge, by realizing a time-discrete version of a 1st order RC filter. (The background is that I'm trying to implement a PLL in software for SDR purposes, but this is a different story...)

My problem is that I thought I understood how to create the difference equation for such a filter, and therefore derive its coefficients. However when I plot the response in MATLAB using the freqz function - with the calculated a and b coefficients - I don't get what looks like an RC filter response.

I referenced the Wikipedia page on this topic (at http://en.wikipedia.org/wiki/Low-pass_filter#Discrete-time_realization), just to make sure I wasn't totally off in the weeds, but it still doesn't help. This details the difference equation as:

yi = alpha * xi + ( 1 - alpha ) * yi-1
where: alpha = sample period / ( RC + sample period )

An example:

fs = 96000.0;                         % Sample rate.
delta_t = 1.0 / fs;                   % Sample period.
fc = 5000.0;                          % Filter cut off frequency.
tau = 1 / ( 2 * pi * fc );            % Time constant of filter.
alpha = delta_t / ( tau + delta_t );  % Smoothing factor per Wikipedia page.
b = [ alpha ];                        % 'b' coefficients
a = [ 1.0, ( 1 - alpha ) ];           % 'a' coefficents
freqz( b, a, 1024, fs );              % 1024 point FFT used.

The result: enter image description here

Any thoughts as to where I'm going wrong? Have I totally misunderstood something?

Thanks in advance.

2 Answers
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