How to convert string to byte array in Python

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Say that I have a 4 character string, and I want to convert this string into a byte array where each character in the string is translated into its hex equivalent. e.g.

str = "ABCD"

I'm trying to get my output to be

array('B', [41, 42, 43, 44])

Is there a straightforward way to accomplish this?

9 Answers

This work in both Python 2 and 3:

>>> bytearray(b'ABCD')
bytearray(b'ABCD')

Note string started with b.

To get individual chars:

>>> print("DEC HEX ASC")
... for b in bytearray(b'ABCD'):
...     print(b, hex(b), chr(b))
DEC HEX ASC
65 0x41 A
66 0x42 B
67 0x43 C
68 0x44 D

Hope this helps

Depending on your needs, this can be one step or two steps

  1. use encode() to convert string to bytes, immutable
  2. use bytearray() to convert bytes to bytearray, mutable
s="ABCD"
encoded=s.encode('utf-8')
array=bytearray(encoded)

The following validation is done in Python 3.7

>>> s="ABCD"
>>> encoded=s.encode('utf-8')
>>> encoded
b'ABCD'
>>> array=bytearray(encoded)
>>> array
bytearray(b'ABCD')

Since none of the answers is producing exactly array('B', [41, 42, 43, 44]) and the answer by avasal fails in Python 3, I post here my alternative:

import array
s = 'ABCD'
a = array.array('B', [ord(c) for c in s])
print(a)

which prints

array('B', [65, 66, 67, 68])

Note that 65-68 is the correct ASCII for "ABCD".

for python 3 it worked for what @HYRY posted. I needed it for a returned data in a dbus.array. This is the only way it worked

s = "ABCD"

from array import array

a = array("B", s)
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