What is the behavior of printing NULL with printf's %s specifier?

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Came across an interesting interview question:

test 1:
printf("test %s\n", NULL);
printf("test %s\n", NULL);

prints:
test (null)
test (null)

test 2:
printf("%s\n", NULL);
printf("%s\n", NULL);
prints
Segmentation fault (core dumped)

Though this might run fine on some systems, atleast mine is throwing a segmentation fault. What would be the best explanation of this behavior? Above code is in C.

Following is my gcc info:

deep@deep:~$ gcc --version
gcc (Ubuntu/Linaro 4.6.3-1ubuntu5) 4.6.3
4 Answers
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