Malloc and array index confusion in C

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I was trying to grasp the malloc function in C, and I wrote the following code:

int i;

int *arr = (int*)malloc(5*sizeof(int)); 

if(arr==NULL){

  printf("Failed to allocate memory for arr...\n");
  exit(1);

}

I thought this meant that only 5 elements could be added to the array. To test out if that was true, I added the following code:

arr[0] = 1;
arr[1] = 2;
arr[2] = 3;
arr[3] = 4;
arr[4] = 5;
arr[5] = 6;
arr[6] = 7;
arr[7] = 8;
arr[8] = 9;

for(i=0;i<9;i++){

    printf("%d\n",arr[i]);

}

Surprisingly, that code compiled and ran perfectly. How was that possible?

4 Answers
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