It is possible in C++ define a function argument to be of more than one type?
#include <iostream>
using namespace std;
class A {
public:
void PrintA() { cout << "A" << endl;}
};
class B {
public:
void PrintB() { cout << "B" << endl;}
};
class C: public A, public B {
public:
C(){;}
};
class D: public A, public B {
public:
D(){;}
};
///
void __printall__(A*a, B*b){
a->PrintA();
b->PrintB();
}
#define printall(a) __printall__(a,a)
///
int main(int argc, char *argv[]){
C c;
D d;
printall(&c);
printall(&d);
}
I want to change the code between the comments with something not using macros. I would not force the pointers cast because I want to preserve the type safety. I would not even introduce another class between C/D and A/B because actually my class hierarchy is a bit more complex of that shown in the code, and it is not desirable to rebase all the class that derive from A or B