how to avoid python numeric literals beginning with "0" being treated as octal?

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I am trying to write a small Python 2.x API to support fetching a job by jobNumber, where jobNumber is provided as an integer. Sometimes the users provide ajobNumber as an integer literal beginning with 0, e.g. 037537. (This is because they have been coddled by R, a language that sanely considers 037537==37537.) Python, however, considers integer literals starting with "0" to be OCTAL, thus 037537!=37537, instead 037537==16223. This strikes me as a blatant affront to the principle of least surprise, and thankfully it looks like this was fixed in Python 3---see PEP 3127.

But I'm stuck with Python 2.7 at the moment. So my users do this:

>>> fetchJob(037537)

and silently get the wrong job (16223), or this:

>>> fetchJob(038537)
File "<stdin>", line 1
 fetchJob(038537)
            ^
SyntaxError: invalid token

where Python is rejecting the octal-incompatible digit.

There doesn't seem to be anything provided via __future__ to allow me to get the Py3K behavior---it would have to be built-in to Python in some manner, since it requires a change to the lexer at least.

Is anyone aware of how I could protect my users from getting the wrong job in cases like this? At the moment the best I can think of is to change that API so it take a string instead of an int.

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