Given this specific line pulled from ifconfig, in my case:
inet 192.168.2.13 netmask 0xffffff00 broadcast 192.168.2.255
How could one extract the 192.168.2.13 part (the local IP address), presumably with regex?
Extracting IP address from a line from ifconfig output with grep
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12 Answers
This code works for me on raspberry pi zero w.
(extract wlan0: inet 192.168.x.y address from ifconfig output)
Search for pattern 'inet 192' in ifconfig output and get the 10th position using space delimiter.
$> ifconfig |grep 'inet 192'|cut -d' ' -f10
Output: 192.168.1.6
If using grep that supports Perl regex:
(your command that pulls mentioned line) | grep -Po 'inet \K[\d\.]+'
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