Test multiple file conditions in one swoop (BASH)?

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Often when writing for the bash shell, one needs to test if a file (or Directory) exists (or doesn't exist) and take appropriate action. Most common amongst these test are...

-e - file exists, -f - file is a regular file (not a directory or device file), -s - file is not zero size, -d - file is a directory, -r - file has read permission, -w - file has write, or -x execute permission (for the user running the test)

This is easily confirmed as demonstrated on this user-writable directory....

#/bin/bash

if [ -f "/Library/Application Support" ]; then
echo 'YES SIR -f is fine'
else echo 'no -f for you'
fi

if [ -w "/Library/Application Support" ]; then
echo 'YES SIR -w is fine'
else echo 'no -w for you'
fi

if [ -d "/Library/Application Support" ]; then
echo 'YES SIR -d is fine'
else echo 'no -d for you'
fi

➝ no -f for you ✓
➝ YES SIR -w is fine ✓
➝ YES SIR -d is fine ✓

My question, although seemingly obvious, and unlikely to be impossible - is how to simply combine these tests, without having to perform them separately for each condition... Unfortunately...

if [ -wd "/Library/Application Support" ]  
  ▶  -wd: unary operator expected

if [ -w | -d "/Library/Application Support" ]   
  ▶  [: missing `]'
  ▶  -d: command not found

if [ -w [ -d "/Library.... ]]   &  if [ -w && -d "/Library.... ] 
  ▶  [: missing `]'

➝ no -wd for you ✖
➝ no -w | -d for you ✖
➝ no [ -w [ -d .. ]] for you ✖
➝ no -w && -d for you ✖

What am I missing here?

6 Answers
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