Calling private method in C++

user_673730 0
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This is purely a theoretical question, I know that if someone declares a method private, you probably shouldn't call it. I managed to call private virtual methods and change private members for instances, but I can't figure out how to call a private non-virtual method (without using __asm). Is there a way to get the pointer to the method? Are there any other ways to do it?

EDIT: I don't want to change the class definition! I just want a hack/workaround. :)

c++
13 Answers

Easiest way to call private method (based on previous answers but a little simpler):

// Your class
class sample_class{
    void private_method(){
        std::cout << "Private method called" << std::endl;
    }
};

// declare method's type
template<typename TClass>
using method_t = void (TClass::*)();

// helper structure to inject call() code
template<typename TClass, method_t<TClass> func>
struct caller{
    friend void call(){
        TClass obj;
        (obj.*func)();
    }
};

// even instantiation of the helper
template struct caller<sample_class,&sample_class::private_method>;

// declare caller
void call();

int main(){
    call(); // and call!
    return 0;
}
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