Built-in factorial function in Haskell

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I know this sounds like a stupid question, but here it is: Is there a built-in factorial in Haskell?

Google gives me tutorials about Haskell explaining how I can implement it myself, and I could not find anything on Hoogle. I don't want to rewrite it each time I need it.

I can use product [1..n] as a replacement, but is there a true Int -> Int factorial built-in function?

factorial haskell
8 Answers
fact n = if n == 0 then 1 else n * fact(n-1)
fact n = foldl(*) 1 [1..n]
fact n = product [1..n]

You can choose either

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