Rounding time in Python

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What would be an elegant, efficient and Pythonic way to perform a h/m/s rounding operation on time related types in Python with control over the rounding resolution?

My guess is that it would require a time modulo operation. Illustrative examples:

  • 20:11:13 % (10 seconds) => (3 seconds)
  • 20:11:13 % (10 minutes) => (1 minutes and 13 seconds)

Relevant time related types I can think of:

  • datetime.datetime \ datetime.time
  • struct_time
modulo rounding time datetime python
8 Answers

I use following code snippet to round to the next hour:

import datetime as dt

tNow  = dt.datetime.now()
# round to the next full hour
tNow -= dt.timedelta(minutes = tNow.minute, seconds = tNow.second, microseconds =  tNow.microsecond)
tNow += dt.timedelta(hours = 1)
user_30289580

Here is a lossy* version of hourly rounding:

dt = datetime.datetime
now = dt.utcnow()
rounded = dt.utcfromtimestamp(round(now.timestamp() / 3600, 0) * 3600)

Same principle can be applied to different time spans.

*The above method assumes UTC is used, as any timezone information will be destroyed in conversion to timestamp.

user_13319780

You could also try pandas.Timestamp.round:

import datetime
import pandas as pd

t = datetime.datetime(2012,12,31,23,44,59,1234)
print(pd.to_datetime(t).round('1min'))
% Timestamp('2012-12-31 23:45:00')

You can perform the following if you want to change the result back to datetime format:

pd.to_datetime(t).round('1min').to_pydatetime()
% datetime.datetime(2012, 12, 31, 23, 45)
user_130971400
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