Does using references instead of pointers, resolve memory leaks in C++?

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Most of memory leaks appear when a pointer of an object returned and programmer forgot to delete it.

for example:

class my_class
{
  ...
};

my_class* func1()
{
  my_class* c = new my_class;
  return c;
}

int main()
{
  my_class* var1 = func1();
  ...
  // Programmer forgot delete the var1: delete var1;
  // -- or --
  // Doesn't know 'delete[] var1;' is correct or 'delete var1;'.
}

Some of memory leaks appear when a pointer to an object created and programmer forgot to delete it.

for example:

class my_class
{
  ...
};

void func2(my_class* p)
{
  ...
}

int main()
{
  my_class* var3 = new my_class;

  func2(var3);

  // Does func2 deletes var3? Programmer doesn't know.
  // -- or --
  // Programmer forgot delete the var3.
}

I use a method to resolve memory leaks but I don't sure about it in complex situations.

My method is: Don't use any pointers (except one place), Just use references instead of pointers.

for example:

class my_class
{
  ...
};

my_class& func1()
{
  my_class* c = new my_class; // except one place.
  return *c;
}

void func2(my_class& p)
{
  ...
}

int main()
{
  my_class& var1 = func1();
  my_class  var2 = func1();

  my_class var3;
  func2(var3);

  // There is nothing to forget.
}

Does using references instead of pointers, resolve memory leaks?

Is it a good method for resolving memory leaks or there are better methods?


Edit:

Some answer of this question don't agree the below code don't have memory leak.

because it is a new question, I ask it seperately.

class my_class
{
  ...
};

my_class& func()
{
  my_class* c = new my_class;
  return *c;
}

int main()
{
  my_class& var1 = func();

  // I think there is no memory leak.
}

I ask it here: Does this code leak memory? (references, new, but no delete)

5 Answers
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