Efficient distance calculation between N points and a reference in numpy/scipy

user_809034 0
Viewed 49860

I just started using scipy/numpy. I have an 100000*3 array, each row is a coordinate, and a 1*3 center point. I want to calculate the distance for each row in the array to the center and store them in another array. What is the most efficient way to do it?

scipy-spatial scipy numpy arrays python
6 Answers
#is it true, to find the biggest distance between the points in surface?

from math import sqrt

n = int(input( "enter the range : "))
x = list(map(float,input("type x coordinates: ").split()))
y = list(map(float,input("type y coordinates: ").split()))
maxdis = 0  
for i in range(n):
    for j in range(n):
        print(i, j, x[i], x[j], y[i], y[j])
        dist = sqrt((x[j]-x[i])**2+(y[j]-y[i])**2)
        if maxdis < dist:

            maxdis = dist
print(" maximum distance is : {:5g}".format(maxdis))
user_106614340
Related