Efficiently find binary strings with low Hamming distance in large set

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Problem:

Given a large (~100 million) list of unsigned 32-bit integers, an unsigned 32-bit integer input value, and a maximum Hamming Distance, return all list members that are within the specified Hamming Distance of the input value.

Actual data structure to hold the list is open, performance requirements dictate an in-memory solution, cost to build the data structure is secondary, low cost to query the data structure is critical.

Example:

For a maximum Hamming Distance of 1 (values typically will be quite small)

And input: 
00001000100000000000000001111101

The values:
01001000100000000000000001111101 
00001000100000000010000001111101 

should match because there is only 1 position in which the bits are different.

11001000100000000010000001111101

should not match because 3 bit positions are different.

My thoughts so far:

For the degenerate case of a Hamming Distance of 0, just use a sorted list and do a binary search for the specific input value.

If the Hamming Distance would only ever be 1, I could flip each bit in the original input and repeat the above 32 times.

How can I efficiently (without scanning the entire list) discover list members with a Hamming Distance > 1.

7 Answers

A common approach (at least common to me) is to divide your bit string in several chunks and query on these chunks for an exact match as pre-filter step. If you work with files, you create as many files as you have chunks (e.g. 4 here) with each chunk permuted in front and then sort the files. You can use a binary search and you can even expand you search above and below a matching chunk for bonus.

You then can perform a bitwise hamming distance computation on the returned results which should be only a smaller subset of your overall dataset. This can be done using data files or SQL tables.

So to recap: Say you have a bunch of 32 bits strings in a DB or files and that you want to find every hash that are within a 3 bits hamming distance or less of your "query" bit string:

  1. create a table with four columns: each will contain an 8 bits (as a string or int) slice of the 32 bits hashes, islice 1 to 4. Or if you use files, create four files, each being a permutation of the slices having one "islice" at the front of each "row"

  2. slice your query bit string the same way in qslice 1 to 4.

  3. query this table such that any of qslice1=islice1 or qslice2=islice2 or qslice3=islice3 or qslice4=islice4. This gives you every string that are within 7 bits (8 - 1) of the query string. If using a file, do a binary search in each of the four permuted files for the same results.

  4. for each returned bit string, compute the exact hamming distance pair-wise with you query bit string (reconstructing the index-side bit strings from the four slices either from the DB or from a permuted file)

The number of operations in step 4 should be much less than a full pair-wise hamming computation of your whole table and is very efficient in practice. Furthermore, it is easy to shard the files in smaller files as need for more speed using parallelism.

Now of course in your case, you are looking for a self-join of sort, that is all the values that are within some distance of each other. The same approach still works IMHO, though you will have to expand up and down from a starting point for permutations (using files or lists) that share the starting chunk and compute the hamming distance for the resulting cluster.

If running in memory instead of files, your 100M 32 bits strings data set would be in the range of 4 GB. Hence the four permuted lists may need about 16GB+ of RAM. Though I get excellent results with memory mapped files instead and must less RAM for similar size datasets.

There are open source implementations available. The best in the space is IMHO the one done for Simhash by Moz, C++ but designed for 64 bits strings and not 32 bits.

This bounded happing distance approach was first described AFAIK by Moses Charikar in its "simhash" seminal paper and the corresponding Google patent:

  1. APPROXIMATE NEAREST NEIGHBOR SEARCH IN HAMMING SPACE

[...]

Given bit vectors consisting of d bits each, we choose N = O(n 1/(1+ ) ) random permutations of the bits. For each random permutation σ, we maintain a sorted order O σ of the bit vectors, in lexicographic order of the bits permuted by σ. Given a query bit vector q, we find the approximate nearest neighbor by doing the following:

For each permutation σ, we perform a binary search on O σ to locate the two bit vectors closest to q (in the lexicographic order obtained by bits permuted by σ). We now search in each of the sorted orders O σ examining elements above and below the position returned by the binary search in order of the length of the longest prefix that matches q.

Monika Henziger expanded on this in her paper "Finding near-duplicate web pages: a large-scale evaluation of algorithms":

3.3 The Results for Algorithm C

We partitioned the bit string of each page into 12 non- overlapping 4-byte pieces, creating 20B pieces, and computed the C-similarity of all pages that had at least one piece in common. This approach is guaranteed to find all pairs of pages with difference up to 11, i.e., C-similarity 373, but might miss some for larger differences.

This is also explained in the paper Detecting Near-Duplicates for Web Crawling by Gurmeet Singh Manku, Arvind Jain, and Anish Das Sarma:

  1. THE HAMMING DISTANCE PROBLEM

Definition: Given a collection of f -bit fingerprints and a query fingerprint F, identify whether an existing fingerprint differs from F in at most k bits. (In the batch-mode version of the above problem, we have a set of query fingerprints instead of a single query fingerprint)

[...]

Intuition: Consider a sorted table of 2 d f -bit truly random fingerprints. Focus on just the most significant d bits in the table. A listing of these d-bit numbers amounts to “almost a counter” in the sense that (a) quite a few 2 d bit- combinations exist, and (b) very few d-bit combinations are duplicated. On the other hand, the least significant f − d bits are “almost random”.

Now choose d such that |d − d| is a small integer. Since the table is sorted, a single probe suffices to identify all fingerprints which match F in d most significant bit-positions. Since |d − d| is small, the number of such matches is also expected to be small. For each matching fingerprint, we can easily figure out if it differs from F in at most k bit-positions or not (these differences would naturally be restricted to the f − d least-significant bit-positions).

The procedure described above helps us locate an existing fingerprint that differs from F in k bit-positions, all of which are restricted to be among the least significant f − d bits of F. This takes care of a fair number of cases. To cover all the cases, it suffices to build a small number of additional sorted tables, as formally outlined in the next Section.

Note: I posted a similar answer to a related DB-only question

Here's a simple idea: do a byte-wise radix sort of the 100m input integers, most significant byte first, keeping track of bucket boundaries on the first three levels in some external structure.

To query, start with a distance budget of d and your input word w. For each bucket in the top level with byte value b, calculate the Hamming distance d_0 between b and the high byte of w. Recursively search that bucket with a budget of d - d_0: that is, for each byte value b', let d_1 be the Hamming distance between b' and the second byte of w. Recursively search into the third layer with a budget of d - d_0 - d_1, and so on.

Note that the buckets form a tree. Whenever your budget becomes negative, stop searching that subtree. If you recursively descend into a leaf without blowing your distance budget, that leaf value should be part of the output.

Here's one way to represent the external bucket boundary structure: have an array of length 16_777_216 (= (2**8)**3 = 2**24), where the element at index i is the starting index of the bucket containing values in range [256*i, 256*i + 255]. To find the index one beyond the end of that bucket, look up at index i+1 (or use the end of the array for i + 1 = 2**24).

Memory budget is 100m * 4 bytes per word = 400 MB for the inputs, and 2**24 * 4 bytes per address = 64 MiB for the indexing structure, or just shy of half a gig in total. The indexing structure is a 6.25% overhead on the raw data. Of course, once you've constructed the indexing structure you only need to store the lowest byte of each input word, since the other three are implicit in the index into the indexing structure, for a total of ~(64 + 50) MB.

If your input is not uniformly distributed, you could permute the bits of your input words with a (single, universally shared) permutation which puts all the entropy towards the top of the tree. That way, the first level of pruning will eliminate larger chunks of the search space.

I tried some experiments, and this performs about as well as linear search, sometimes even worse. So much for this fancy idea. Oh well, at least it's memory efficient.

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