Getting the array length of a 2D array in Java

user_432209 0
Viewed 694605

I need to get the length of a 2D array for both the row and column. I’ve successfully done this, using the following code:

public class MyClass {

 public static void main(String args[])
    {
  int[][] test; 
  test = new int[5][10];

  int row = test.length;
  int col = test[0].length;

  System.out.println(row);
  System.out.println(col);
    }
}

This prints out 5, 10 as expected.

Now take a look at this line:

  int col = test[0].length;

Notice that I actually have to reference a particular row, in order to get the column length. To me, this seems incredibly ugly. Additionally, if the array was defined as:

test = new int[0][10];

Then the code would fail when trying to get the length. Is there a different (more intelligent) way to do this?

multidimensional-array arrays java
12 Answers

It was really hard to remember that 

    int numberOfColumns = arr.length;
    int numberOfRows = arr[0].length;

Let's understand why this is so and how we can figure this out when we're given an array problem. From the below code we can see that rows = 4 and columns = 3:

    int[][] arr = { {1, 1, 1, 1}, 

                    {2, 2, 2, 2}, 

                    {3, 3, 3, 3} };

arr has multiple arrays in it, and these arrays can be arranged in a vertical manner to get the number of columns. To get the number of rows, we need to access the first array and consider its length. In this case, we access [1, 1, 1, 1] and thus, the number of rows = 4. When you're given a problem where you can't see the array, you can visualize the array as a rectangle with n X m dimensions and conclude that we can get the number of rows by accessing the first array then its length. The other one (arr.length) is for the columns.

user_88153710

If you have this array:

String [][] example = {{{"Please!", "Thanks"}, {"Hello!", "Hey", "Hi!"}},
                       {{"Why?", "Where?", "When?", "Who?"}, {"Yes!"}}};

You can do this:

example.length;

= 2

example[0].length;

= 2

example[1].length;

= 2

example[0][1].length;

= 3

example[1][0].length;

= 4

Admin1

.length = number of rows / column length

[0].length = number of columns / row length

user_115108420

Example Array 1:

int arr[][] = { { 1, 3, 1, 5 },
                 { 2, 2, 4, 1 },
                 { 5, 0, 2, 3 },
                 { 0, 6, 1, 2 } };

Example Array 2:

int arr[][] = { { 1, 3, 1 },
                 { 2, 2, 4 },
                 { 5, 0, 2 },
                 { 0, 6, 1 } };

Below function will work for any Symmetric and Asymmetric Array Matrix


 row_Count = arr.length
 column_Count = arr[0].length
user_82912700 
import java.util.Arrays;

public class Main {

    public static void main(String[] args) 
    {

        double[][] test = { {100}, {200}, {300}, {400}, {500}, {600}, {700}, {800}, {900}, {1000}};

        int [][] removeRow = { {0}, {1}, {3}, {4}, };

        double[][] newTest = new double[test.length - removeRow.length][test[0].length];

        for (int i = 0, j = 0, k = 0; i < test.length; i++) {
            if (j < removeRow.length) {
                if (i == removeRow[j][0]) {
                    j++;
                    continue;
                }
            }
            newTest[k][0] = test[i][0];
            k++;
        }

        System.out.println(Arrays.deepToString(newTest));   
    }
}
user_106367400

With Java 8, allow you doing something more elegant like this:

int[][] foo = new int[][] {
        new int[] { 1, 2, 3 },
        new int[] { 1, 2, 3, 4},
    };

int length = Arrays.stream(array).max(Comparator.comparingInt(ArrayUtils::getLength)).get().length
user_103930670
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