Parse NSURL query property

Question

I have a URL like myApp://action/1?parameter=2&secondparameter=3

With the property query I get following part of my URL

parameter=2&secondparameter=3

Is there any way easy to put this in a NSDictionary or an Array?

Thx a lot

user_770313 · Answer

Fairly compact approach:

    func stringParamsToDict(query: String) -> [String: String] {
        let params = query.components(separatedBy: "&").map {
            $0.components(separatedBy: "=")
        }.reduce(into: [String: String]()) { dict, pair in
            if pair.count == 2 {
                dict[pair[0]] = pair[1]
            }
        }
        return params
    }

Parse NSURL query property

17 Answers