Create date from day, month, year fields in MySQL

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I am currently developing an application that displays documents and allows the members to search for these documents by a number of different parameters, one of them being date range.

The problem I am having is that the database schema was not developed by myself and the creator of the database has created a 'date' table with fields for 'day','month','year'.

I would like to know how I can select a specific day, month, year from the table and create a date object in SQL so that I can compare dates input by the user using BETWEEN.

Below is the structure of the date table:

CREATE TABLE IF NOT EXISTS `date` (
  `deposition_id` varchar(11) NOT NULL default '',
  `day` int(2) default NULL,
  `month` int(2) default NULL,
  `year` int(4) default NULL,
  PRIMARY KEY  (`deposition_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
datetime mysql sql database
6 Answers

Expanding this answer, here's my take on it:

DELIMITER $$

CREATE FUNCTION fn_year_month_to_date(var_year INTEGER,
    var_month enum('01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12')
    )
RETURNS DATE
BEGIN
    RETURN (MAKEDATE(var_year, 1) + INTERVAL (var_month - 1) MONTH);
END $$

DELIMITER ;

SELECT fn_year_month_to_date(2020, 12)
;
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