How can I escape a double quote inside double quotes?

user_463300 0
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How can I escape double quotes inside a double string in Bash?

For example, in my shell script

#!/bin/bash

dbload="load data local infile \"'gfpoint.csv'\" into table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY \"'\n'\" IGNORE 1 LINES"

I can't get the ENCLOSED BY '\"' with double quote to escape correctly. I can't use single quotes for my variable, because I want to use variable $dbtable.

quotes bash
9 Answers

Store the double quote character in a variable:

dqt='"'
echo "Double quotes ${dqt}X${dqt} inside a double quoted string"

Output:

Double quotes "X" inside a double quoted string
user_89367900

For use with variables that might contain spaces in you Bash script, use triple quotes inside the main quote, e.g.:

[ "$(date -r """$touchfile""" +%Y%m%d)" -eq "$(date +%Y%m%d)" ]
user_27560660
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